java – 设置属性值时出错;嵌套异常是org.springframework.beans.NotWritablePropertyException：

我试图使用Spring实用程序ResultSetExtractor从MySQL数据库获取数据,但我得到以下异常：

Exception in thread "main" org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'edao' defined in class path resource [applicationContext2.xml]: Error setting property values; nested exception is org.springframework.beans.NotWritablePropertyException: Invalid property 'jdbcTemplate' of bean class [org.resultset.EmployeeDao]: Bean property 'jdbcTemplate' is not writable or has an invalid setter method. Does the parameter type of the setter match the return type of the getter?
    at org.springframework.beans.factory.support.AbstractAutowireCapablebeanfactory.applyPropertyValues(AbstractAutowireCapablebeanfactory.java:1344)
    at org.springframework.beans.factory.support.AbstractAutowireCapablebeanfactory.populateBean(AbstractAutowireCapablebeanfactory.java:1067)
    at org.springframework.beans.factory.support.AbstractAutowireCapablebeanfactory.doCreateBean(AbstractAutowireCapablebeanfactory.java:511)
    at org.springframework.beans.factory.support.AbstractAutowireCapablebeanfactory.createBean(AbstractAutowireCapablebeanfactory.java:450)
    at org.springframework.beans.factory.support.Abstractbeanfactory$1.getobject(Abstractbeanfactory.java:290)
    at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222)
    at org.springframework.beans.factory.support.Abstractbeanfactory.doGetBean(Abstractbeanfactory.java:287)
    at org.springframework.beans.factory.support.Abstractbeanfactory.getBean(Abstractbeanfactory.java:189)
    at org.springframework.beans.factory.support.DefaultListablebeanfactory.preInstantiateSingletons(DefaultListablebeanfactory.java:562)
    at org.springframework.context.support.AbstractApplicationContext.finishbeanfactoryInitialization(AbstractApplicationContext.java:871)
    at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:423)
    at org.springframework.context.support.ClasspathXmlApplicationContext.sspathXmlApplicationContext.java:139)
    at org.springframework.context.support.ClasspathXmlApplicationContext.sspathXmlApplicationContext.java:83)
    at org.resultset.Test.main(Test.java:11)
Caused by: org.springframework.beans.NotWritablePropertyException: Invalid property 'jdbcTemplate' of bean class [org.resultset.EmployeeDao]: Bean property 'jdbcTemplate' is not writable or has an invalid setter method. Does the parameter type of the setter match the return type of the getter?
    at org.springframework.beans.BeanWrapperImpl.setPropertyValue(BeanWrapperImpl.java:1012)
    at org.springframework.beans.BeanWrapperImpl.setPropertyValue(BeanWrapperImpl.java:857)
    at org.springframework.beans.AbstractPropertyAccessor.setPropertyValues(AbstractPropertyAccessor.java:76)
    at org.springframework.beans.AbstractPropertyAccessor.setPropertyValues(AbstractPropertyAccessor.java:58)
    at org.springframework.beans.factory.support.AbstractAutowireCapablebeanfactory.applyPropertyValues(AbstractAutowireCapablebeanfactory.java:1341)
    ... 13 more

Employee.java

public class Employee {

    private int id;  
    private String name;  
    private float salary;
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public float getSalary() {
        return salary;
    }
    public void setSalary(float salary) {
        this.salary = salary;
    }
    public Employee(int id,String name,float salary) {
        super();
        this.id = id;
        this.name = name;
        this.salary = salary;
    } 

    public Employee()
    {

    }

}

EmployeeDao.java

public class EmployeeDao {  
private JdbcTemplate template;  

public void setTemplate(JdbcTemplate template) {  
    this.template = template;  
}  

public ListsqlException,DataAccessException {  

        List

Test.java

public class Test {  

public static void main(String[] args) {  
  ApplicationContext ctx=new ClasspathXmlApplicationContext("applicationContext2.xml");  
  EmployeeDao dao=(EmployeeDao)ctx.getBean("edao");  
  Liststem.out.println(e);  

  }  

}  

和applicationContext2.xml

spring-beans-3.0.xsd">  

MysqL.jdbc.Driver" />  
MysqL://loclahost:3306/test1" />  

这些都是我正在使用的java文件.它说setter的返回类型与getter不匹配,但我检查了它,并且它在那里是正确的.

最佳答案

问题在于

< bean id =“edao”class =“org.resultset.EmployeeDao”>
     < property name =“jdbcTemplate”ref =“jdbcTemplate”>< / property>
< /豆腐>

尝试将name =“jdbcTemplate”更改为name =“template”.由于你已经将名称命名为jdbcTemplate,spring将在EmployeeDao类中搜索名为setJdbcTemplate()的setter方法,但是你拥有的acutal方法是setTemplate()

版权声明：本文内容由互联网用户自发贡献，该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请发送邮件至 [email protected] 举报，一经查实，本站将立刻删除。