我有一个ASP.NET MVC 5应用程序.我正在尝试发送带有Model数据的POST请求,并且还包括用户选择的文件.
这是我的viewmodel(为清楚起见已简化):
public class Model
{
public string Text { get; set; }
public long Id { get; set; }
}
这是控制器动作:
[HttpPost]
public ActionResult UploadFile(long userId, Model model)
{
foreach (string file in Request.Files)
{
// process files
}
return View("Index");
}
HTML输入元素:
<div>
<input type="file" name="UploadFile" id="txtUploadFile" />
</div>
和JavaScript代码:
$('#txtUploadFile').on('change', function (e) {
var data = new FormData();
for (var x = 0; x < files.length; x++) {
data.append("file" + x, files[x]);
}
data.append("userId", 1);
data.append("model", JSON.stringify({ Text: 'test text', Id: 3 }));
$.ajax({
type: "POST",
url: '/Home/UploadFile',
contentType: false,
processData: false,
data: data,
success: function (result) { },
error: function (xhr, status, p3, p4) { }
});
});
问题是当请求到达控制器操作时,我已经填充了文件和“ userId”,但是“ model”参数始终为空.填充FormData对象时我做错什么了吗?
解决方法:
这是我与MVC5和IE11 / Chrome一起测试的内容
视图
<script>
$(function () {
$("#form1").submit(function () {
/*You can also inject values to suitable named hidden fields*/
/*You can also inject the whole hidden filed to form dynamically*/
$('#name2').val(Date);
var formData = new FormData($(this)[0]);
$.ajax({
url: $(this).attr('action'),
type: $(this).attr('method'),
data: formData,
async: false,
success: function (data) {
alert(data)
},
error: function(){
alert('error');
},
cache: false,
contentType: false,
processData: false
});
return false;
});
});
</script>
<form id="form1" action="/Home/Index" method="post" enctype="multipart/form-data">
<input type="text" id="name1" name="name1" value="value1" />
<input type="hidden" id ="name2" name="name2" value="" />
<input name="file1" type="file" />
<input type="submit" value="Sublit" />
</form>
控制者
public class HomeController : Controller
{
[HttpGet]
public ActionResult Index()
{
return View();
}
[HttpPost]
public ActionResult Index(HttpPostedFileBase file1, string name1, string name2)
{
var result = new List<string>();
if (file1 != null)
result.Add(string.Format("{0}: {1} bytes", file1.FileName, file1.ContentLength));
else
result.Add("No file");
result.Add(string.Format("name1: {0}", name1));
result.Add(string.Format("name2: {0}", name2));
return Content(string.Join(" - ", result.ToArray()));
}
}
感谢Silver89的answer
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