我有三个页面:test.PHP,script.js和main.PHP.
Main.PHP正在使用html5拖放以及来自script.js的简单ajax脚本,以便发布并激活test.PHP. (旁注,我希望main.PHP传递< img id =“s1”/>作为POST变量.经过几个小时的研究和一百次左右的测试和修改,我无法弄清楚为什么我无法获得触发帖子.任何建议都将非常感谢.这是我的代码:
test.PHP(包含一个简单的PHP脚本,加载时将通用记录插入我的DB)
的script.js
function drop(id, event) {
$.ajax({
url: "test.PHP",
type: "POST",
data: {
id: id,
event: event
},
success: function () {
console.log('great success');
return true
}
});
return false;
}
和main.PHP
<!DOCTYPE HTML>
<html>
<head>
<script type="text/javascript" src="/js/jquery.js"></script>
<script type="text/javascript" src="/js/script.js"></script>
<header class="main-header" role="banner"><center>
<img src="lampettalogo.jpg" height="90" width="400"alt="Banner Image"/></center>
</header>
<style>
#1 {width:auto;height:auto;padding:1px;border:1px solid #aaaaaa;}
#2 {width:auto;height:auto;padding:1px;border:1px solid #aaaaaa;}
#3 {width:auto;height:auto;padding:1px;border:1px solid #aaaaaa;}
#4 {width:auto;height:auto;padding:1px;border:1px solid #aaaaaa;overflow: auto;}
</style>
</head>
<body>
<div id="1" ondrop="drop(event)" ondragover="allowDrop(event)">
<?PHP
include "database_connection.PHP";
///////////////////////////////////////////////////////////////////////////////////////////////
/* check connection */
if (MysqLi_connect_errno()) {
printf("Connect Failed: %s\n", MysqLi_connect_error());
exit();
}
else
{
}
$query = "SELECT * FROM ss where currentZone = 1";
if ($result = MysqLi_query($link, $query)) {
/* fetch associative array */
while ($row = MysqLi_fetch_assoc($result)) {
echo "<img id='{$row["sID"]}' src='{$row["photoLink"]}.jpg' draggable='true' ondragstart='drag(event)' width='75' height='75'>" ;
}
/* free result set */
MysqLi_free_result($result);
}
MysqLi_close($link);
/////////////////////////////////////////////////////////////////////////////////
?>
</div>
<div id="2" ondrop="drop(event)" ondragover="allowDrop(event)">
<?PHP
include "database_connection.PHP";
$query = "SELECT * FROM ss where currentZone = 2";
if ($result = MysqLi_query($link, $query)) {
/* fetch associative array */
while ($row = MysqLi_fetch_assoc($result)) {
echo "<img id='{$row["sID"]}' src='{$row["photoLink"]}.jpg' draggable='true' ondragstart='drag(event)' ondrop='drop(event)' width='75' height='75'>" ;
}
/* free result set */
MysqLi_free_result($result);
}
MysqLi_close($link);
?>
</div>
<div id="3" ondrop="drop(event)" ondragover="allowDrop(event)">
<?PHP
include "database_connection.PHP";
$query = "SELECT * FROM ss where currentZone = 3";
if ($result = MysqLi_query($link, $query)) {
/* fetch associative array */
while ($row = MysqLi_fetch_assoc($result)) {
echo "<img id='{$row["sID"]}' src='{$row["photoLink"]}.jpg' draggable='true' ondragstart='drag(event)' width='75' height='75'>" ;
}
/* free result set */
MysqLi_free_result($result);
}
MysqLi_close($link);
?>
</div>
<div id="4" ondrop="drop(event)" ondragover="allowDrop(event)">
<?PHP
include "database_connection.PHP";
$query = "SELECT * FROM ss where currentZone = 4";
if ($result = MysqLi_query($link, $query)) {
/* fetch associative array */
while ($row = MysqLi_fetch_assoc($result)) {
echo "<img id='{$row["sID"]}' src='{$row["photoLink"]}.jpg' draggable='true' ondragstart='drag(event)' width='75' height='75'>" ;
}
/* free result set */
MysqLi_free_result($result);
}
MysqLi_close($link);
?>
</div>
<div id="4" ondrop="drop(event)" ondragover="allowDrop(event)">
<?PHP
include "database_connection.PHP";
$query = "SELECT * FROM ss where currentZone = 0";
if ($result = MysqLi_query($link, $query)) {
/* fetch associative array */
while ($row = MysqLi_fetch_assoc($result)) {
echo "<img id='{$row["sID"]}' src='{$row["photoLink"]}.jpg' draggable='true' ondragstart='drag(event)' width='75' height='75'>" ;
}
/* free result set */
MysqLi_free_result($result);
}
MysqLi_close($link);
?>
</div>
</body>
</html>
解决方法:
在drop(id,e)方法中,除了allowDrop方法之外,还可以考虑以下内容.使用FileReader类读取您的文件.
function drop(id, e) {
if (e.dataTransfer && e.dataTransfer.files.length != 0) {
var file = e.dataTransfer.files[0], // Only the first file.
reader = new FileReader();
reader.readAsDataURL(file);
reader.onload = function (event) {
console.log(file.name);
$.ajax({
url: "test.PHP",
type: "POST",
data: {
id: id,
fileName: file.name, // Your file name.
file: event.target.result // Your file.
},
success: function () {
console.log('great success');
return true
}
});
};
}
}
在HTML中,您还需要传递id中的值.例如,您可以执行以下操作将$row [“sID”]打印到method参数中.
<div id="1" ondrop="drop('<?PHP echo $row["sID"]; ?>', event)" ondragover="allowDrop(event)">
在PHP脚本上,您需要能够接收POSTed文件.一个例子如下所示.
$data = $_POST['file'];
$fileName = $_POST['fileName'];
$id = $_POST['id'];
$serverFile = $fileName . "-" . time(); // Appends timestamp so that files of the same name wouldn't be overwritten.
$fp = fopen('/uploads/' . $serverFile, 'w');
fwrite($fp, $data);
fclose($fp);
$returnData = array( "serverFile" => $serverFile );
echo json_encode($returnData);
有关示例,请参见此plunker.将文件拖放到div中,然后观察控制台日志.
编辑
理解你想要拖放元素.
以下是更新的plunker.
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