微信公众号搜"智元新知"关注
微信扫一扫可直接关注哦!

单元测试 – 单元测试Angular 2 authGuard;间谍方法没有被调用

我正在尝试对我的auth警卫服务进行单元测试.从 this answer开始,我能够做到这一点,但现在当我为此进行单元测试时,它表示预期的间谍导航已被调用.

如何让我的间谍路由器在服务中用作this.router?

AUTH-guard.service.ts

import { Injectable } from '@angular/core';
import { Router,CanActivate } from '@angular/router';

@Injectable()
export class AuthGuardService {

  constructor(private router:Router) { }

  public canActivate() {
    const authToken = localStorage.getItem('auth-token');
    const tokenExp = localStorage.getItem('auth-token-exp');
    const hasAuth = (authToken && tokenExp);

    if(hasAuth && Date.Now() < +tokenExp){
      return true;
    }
    this.router.navigate(['/login']);
    return false;
  }
}

AUTH-guard.service.spec.ts

import { Testbed,async,inject } from '@angular/core/testing';
import { RouterTestingModule } from '@angular/router/testing';

import { AuthGuardService } from './auth-guard.service';

describe('AuthGuardService',() => {
  let service:AuthGuardService = null;
  let router = {
    navigate: jasmine.createSpy('navigate')
  };

  beforeEach(() => {
    Testbed.configureTestingModule({
      providers: [
        AuthGuardService,{provide:RouterTestingModule,useValue:router}
      ],imports: [RouterTestingModule]
    });
  });

  beforeEach(inject([AuthGuardService],(agService:AuthGuardService) => {
    service = agService;
  }));

  it('checks if a user is valid',() => {
    expect(service.canActivate()).toBeFalsy();
    expect(router.navigate).toHaveBeenCalled();
  });
});

将RouterTestingModule替换为Router,如示例中所示,回答抛出模块’DynamicTestModule’导入的意外值’undefined’.

解决方法

而不是存根路由器,在router.navigate()方法上使用依赖注入和间谍:

import { Testbed,inject } from '@angular/core/testing';
import { RouterTestingModule } from '@angular/router/testing';
import { Router } from '@angular/router';

import { AuthGuardService } from './auth-guard.service';

describe('AuthGuardService',() => {

  beforeEach(() => {
    Testbed.configureTestingModule({
      providers: [AuthGuardService],imports: [RouterTestingModule]
    });
  });

  it('checks if a user is valid',// inject your guard service AND Router
    async(inject([AuthGuardService,Router],(auth,router) => {

      // add a spy
      spyOn(router,'navigate');

      expect(auth.canActivate()).toBeFalsy();
      expect(router.navigate).toHaveBeenCalled();
    })
  ));
});

https://plnkr.co/edit/GNjeJSQJkoelIa9AqqPp?p=preview

版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 [email protected] 举报,一经查实,本站将立刻删除。

相关推荐