linux-使用sed在两种模式之间进行打印

这个问题已经在这里有了答案：            >            How to select lines between two marker patterns which may occur multiple times with awk/sed                                    9个
>            How to print lines between two patterns, inclusive or exclusive (in sed, AWK or Perl)?                                    7个
所以我在deleting the text between two patterns和printing the text between two delimiters上找到了很多东西,但是在使用bash函数在两个模式之间打印文本时,我什么都没找到.

如果我有：

"Alas poor Yorik, I knew him well"

并且我想打印介于“ poor”和“ well”(不包括)之间的所有内容,我将得到：

" Yorik, I knew him "

如何使用sed或awk之类的方法实现此目的？

解决方法:

dtpwmbp:~ pwadas$echo "Alas poor Yorik, I knew him well" | sed -e 's/^.*poor //g;s/ well.*$//g'
Yorik, I knew him
dtpwmbp:~ pwadas$echo "Alas poor Yorik, I knew him well" | awk '{sub(/.*poor /,"");sub(/ well.*/,"");print;}'
Yorik, I knew him

文件输入的用法：

dtpwmbp:~ pwadas$echo "Alas poor Yorik, I knew him well" > infile
dtpwmbp:~ pwadas$cat infile 
Alas poor Yorik, I knew him well
dtpwmbp:~ pwadas$cat infile | sed -e 's/^.*poor //g;s/ well.*$//g'
Yorik, I knew him
dtpwmbp:~ pwadas$sed -e 's/^.*poor //g;s/ well.*$//g' < infile
Yorik, I knew him
dtpwmbp:~ pwadas$cat infile | awk '{sub(/.*poor /,"");sub(/ well.*/,"");print;}'
Yorik, I knew him
dtpwmbp:~ pwadas$awk '{sub(/.*poor /,"");sub(/ well.*/,"");print;}' < infile 
Yorik, I knew him