linux – 如何通过存储在单个变量中的引号传递命令行参数？

我想从shell脚本调用外部应用程序,但是这个shell脚本在单个变量中获取参数(来自其他脚本).一切都没问题,直到我不必为单个参数使用双引号,而是用空格分隔的单词.

这是我的问题的简化示例(sh_param只打印所有传递的参数)：

#!/bin/sh

pass() {
    echo "Result with \$@"
    ./sh_param $@
    echo "Result with \"\$@\""
    ./sh_param "$@"
    echo "Result with \$*"
    ./sh_param $*
    echo "Result with \"\$*\""
    ./sh_param "$*"
}

pass '"single param" separate params'

和结果(sh_param只打印所有传递的参数)：

Result with $@
Param: "single
Param: param"
Param: separate
Param: params
Result with "$@"
Param: "single param" separate params
Result with $*
Param: "single
Param: param"
Param: separate
Param: params
Result with "$*"
Param: "single param" separate params

而且我要：

Param: single param
Param: separate
Param: params

解决方法:

脚本

pass() {
  echo 'Result with "$@"'
  sh_param "$@"
}

sh_param() {
  for i in "$@"
  do
    echo Param: $i
  done
}

pass "single param" separate param

结果

Result with "$@"
Param: single param
Param: separate
Param: param