linux – grep awk忽略字符

我正在尝试grep“option dhcp-server-identifier”的值,即192.168.75.1;

我不知道如何忽略分号“;”在IP地址的末尾.

[root@localhost ~]# cat /var/lib/dhclient/dhclient-eth0.leases
lease {
interface "eth0";
fixed-address 192.168.75.54;
option subnet-mask 255.255.255.0;
option routers 192.168.75.1;
option dhcp-lease-time 4294967295;
option dhcp-message-type 5;
option domain-name-servers 192.168.75.1,8.8.8.8;
option dhcp-server-identifier 192.168.75.1;
option broadcast-address 192.168.75.255;
option host-name "centos-64-x86-64";
option domain-name "cs2cloud.internal";
renew 1 2081/12/15 18:43:55;
rebind 2 2132/12/30 03:09:24;
expire 6 2150/01/03 21:58:02;
}

我尝试了以下内容

grep  dhcp-server-identifier /var/lib/dhclient/dhclient-eth0.leases | awk '{print $3}' 

结果是192.168.75.1;

谢谢

解决方法:

使用awk

awk -F" |;" '/dhcp-server-identifier/ {print $3}' /var/lib/dhclient/dhclient-eth0.leases
192.168.75.1