How Many Fibs?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3098 Accepted Submission(s): 1232
Problem Description
Recall the deFinition of the Fibonacci numbers:
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b,calculate how many Fibonacci numbers are in the range [a,b].
f1 := 1
f2 := 2
fn := fn-1 + fn-2 (n >= 3)
Given two numbers a and b,calculate how many Fibonacci numbers are in the range [a,b].
Input
The input contains several test cases. Each test case consists of two non-negative integer numbers a and b. Input is terminated by a = b = 0. Otherwise,a <= b <= 10^100. The numbers a and b are given with no superfluous leading zeros.
Output
For each test case output on a single line the number of Fibonacci numbers fi with a <= fi <= b.
Sample Input
10 100 1234567890 9876543210 0 0
Sample Output
5 4
import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner input=new Scanner(system.in); BigInteger f[]=new BigInteger[505]; f[0]=BigInteger.valueOf(1); f[1]=BigInteger.valueOf(2); for(int i=2;i<502;i++){ f[i]=f[i-1].add(f[i-2]); } while(true){ BigInteger a=input.nextBigInteger(); BigInteger b=input.nextBigInteger(); if(a.equals(BigInteger.ZERO)&&b.equals(BigInteger.ZERO)) break; int sum=0; for(int i=0;i<502&&b.compareto(f[i])>=0;i++){ if(f[i].compareto(a)>=0) sum++; } System.out.println(sum); } } }
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