C++递减指针

#include <iostream>

using namespace std;
const int MAX = 3;

int main () {
   int  var[MAX] = {10, 100, 200};
   int  *ptr;

   // let us have address of the last element in pointer.
   ptr = &var[MAX-1];

   for (int i = MAX; i > 0; i--) {
      cout << Address of var[ << i << ] = ;
      cout << ptr << endl;

      cout << Value of var[ << i << ] = ;
      cout << *ptr << endl;

      // point to the prevIoUs location
      ptr--;
   }

   return 0;
}