鉴于此代码:
public class Car { public virtual int CarId { get; set; } public virtual string TypeName { get; set; } public ConvertableNullable<double> Price { get; set; } }
ConvertableNullable只是Nullable的一种解决方法,但它并不是从它继承的.
现在,这是我的简单上下文,我将汽车类映射到实体,并映射它的每个属性
public class MyDBContext : DbContext { public MyDBContext() : base( "data source=.;initial catalog=newDB1;integrated security=True;" + "multipleactiveresultsets=True;App=EntityFramework") { } protected override void OnModelCreating(DbModelBuilder modelBuilder) { base.OnModelCreating(modelBuilder); modelBuilder.Entity<Car>().HasKey(x=>x.CarId); modelBuilder.Entity<Car>().Property(x => x.TypeName); modelBuilder.Entity<Car>().Property(x => x.Price); } public DbSet<Car> Cars { get; set; } }
现在当我尝试处理这个上下文时,它会引发异常
var db = new MyDBContext(); // Throws exception "The property 'Price' is not a declared // property on type 'Car'. Verify that the property has not // been explicitly excluded from the model by using the Ignore // method or NotMappedAttribute data annotation. Make sure that // it is a valid primitive property." var c = db.Cars.ToList();
有什么建议??
解决方法
唯一的解决方案是使用这样的东西:
public class Car { public virtual int CarId { get; set; } public virtual string TypeName { get; set; } // This must be accessible to the mapping public double? PriceData { get; set; } public ConvertableNullable<double> Price { get { // Return data from PriceData } set { // Set data to PriceData } } }
您的映射将是:
modelBuilder.Entity<Car>().HasKey(x=>x.CarId); modelBuilder.Entity<Car>().Property(x => x.TypeName); modelBuilder.Entity<Car>().Property(x => x.PriceData).HasColumnName("Price"); modelBuilder.Entity<Car>().Ignore(x => x.Price);
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