c# – 为structure-map 3中的DecorateAllWith()方法定义过滤器

我使用以下语句来装饰我的所有ICommandHandlers<>与Decorator1<>：

ObjectFactory.Configure(x =>
{
   x.For(typeof(ICommandHandler<>)).DecorateallWith(typeof(Decorator1<>));
});

但是因为Decorator1<>实现ICommandHandlers<>,Decorator1<> class也装饰自己.

因此,问题是当我注册所有ICommandHandler<>时,Decorator1无意中注册.
我怎样才能过滤DecorateWithAll()来装饰所有ICommandHandler<>,除了Decorator1<>？

解决方法

ObjectFactory已经过时了.

您可以排除Decorator1<>从注册为香草ICommandHandler<>使用这样的代码：

var container = new Container(config =>
{
    config.Scan(scanner =>
    {
        scanner.AssemblyContainingType(typeof(ICommandHandler<>));
        scanner.Exclude(t => t == typeof(Decorator1<>));
        scanner.ConnectImplementationsToTypesClosing(typeof(ICommandHandler<>));
    });
    config.For(typeof(ICommandHandler<>)).DecorateallWith(typeof(Decorator1<>));
});

UPDATE

对于多个模块,您可以使用The Registry DSL组成应用程序的一部分

using StructureMap;
using StructureMap.Configuration.DSL;

public class CommandHandlerRegistry : Registry
{
    public CommandHandlerRegistry()
    {
        Scan(scanner =>
        {
            scanner.AssemblyContainingType(typeof(ICommandHandler<>));
            scanner.Exclude(t => t == typeof(Decorator1<>));
            scanner.ConnectImplementationsToTypesClosing(typeof(ICommandHandler<>));
        });
        For(typeof(ICommandHandler<>)).DecorateallWith(typeof(Decorator1<>));
    }
}

只有组合根需要了解所有注册表实现.

var container = new Container(config =>
{
    config.AddRegistry<CommandHandlerRegistry>();
});

您甚至可以选择在运行时查找所有Registry实例(您仍需要确保加载所有必需的程序集)

var container = new Container(config =>
{
    var registries = (
        from assembly in AppDomain.CurrentDomain.GetAssemblies()
        from type in assembly.DefinedTypes
        where typeof(Registry).IsAssignableFrom(type)
        where !type.IsAbstract
        where !type.Namespace.StartsWith("StructureMap")
        select Activator.CreateInstance(type))
        .Cast<Registry>();

    foreach (var registry in registries)
    {
        config.AddRegistry(registry);
    }
});