我想显示特定行的每小时(1小时时间间隔)内当前数据输入的计数,最后显示所有小时的累计.
表详情:
表详情:
CREATE TABLE [dbo].[ProductTable] ( [Id] INT IDENTITY (1,1) NOT NULL,[ProductID] INT NOT NULL,[EmployeeID] INT NOT NULL,[Operation] VARCHAR (50) NOT NULL,[Section] NCHAR (10) NOT NULL,[Line] INT NOT NULL,[Date] DATETIME DEFAULT (getdate()) NULL,PRIMARY KEY CLUSTERED ([Id] ASC),);
我正在使用Microsoft Visual Studio sql服务器
我写了这么多,但不知道每小时都要概括一下
SELECT COUNT(Id) AS Expr1 FROM ProductTable WHERE (Line = 2) AND (CONVERT(VARCHAR(10),Date,105) = CONVERT(VARCHAR(10),GETDATE(),105)) AND (DATEPART(hour,GETDATE()) BETWEEN 9 AND 10)`
解决方法
听起来你想按小时分组
SELECT DATEPART(hour,date) as TimeOfDay,COUNT(Id) AS Entries FROM ProductTable WHERE (Line = 2) AND cast ([date] as date) =cast (getdate() as date) GROUP BY DATEPART(hour,date)
要获得一天中所有小时的累计,请使用分组集
SELECT ISNULL(cast(DATEPART(hour,[date]) as varchar(5)),'Total') as TimeOfDay,COUNT(Id) AS Entries FROM ProductTable WHERE (Line = 2) AND cast ([date] as date) =cast (getdate() as date) GROUP BY GROUPING SETS (DATEPART(hour,[date]),()) ORDER BY ISNULL(cast(DATEPART(hour,'Total')
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