c# – 最快的阵列初始化？

在我的应用程序中,我需要一个大的常量(实际上是静态只读)对象数组.数组在类型的静态构造函数中初始化.

该数组包含超过一千个项目,当首次使用该类型时,我的程序经历了严重的减速.我想知道是否有办法在C#中快速初始化大型数组.

public static class XSampa {
    public class XSampaPair : IComparable<XSampaPair> {
        public XSampaPair GetReverse() {
            return new XSampaPair(Key,Target);
        }
        public string Key { get; private set; }
        public string Target { get; private set; }
        internal XSampaPair(string key,string target) {
            Key = key;
            Target = target;
        }
        public int Compareto(XSampaPair other) {
            if (other == null)
                throw new ArgumentNullException("other","Cannot compare with Null.");
            if (Key == null)
                throw new NullReferenceException("Key is null!");
            if (other.Key == null)
                throw new NullReferenceException("Key is null!");
            if (Key.Length == other.Key.Length)
                return string.Compare(Key,other.Key,StringComparison.InvariantCulture);
            return other.Key.Length - other.Key;
        }
    }    
    private static readonly XSampaPair[] pairs,reversedPairs;
    public static string ParseXSampaToIpa(this string xsampa) {
        // Parsing code here...
    }
    public static string ParseIpaToXSampa(this string ipa) {
        // reverse code here...
    }
    static XSampa() {
        pairs = new [] {
            new XSampaPair("a","\u0061"),new XSampaPair("b","\u0062"),new XSampaPair("b_<","\u0253"),new XSampaPair("c","\u0063"),// And many more pairs initialized here...
        };
        var temp = pairs.Select(x => x.GetReversed());
        reversedPairs = temp.ToArray();
        Array.sort(pairs);
        Array.sort(reversedPairs);
    }
}

PS：我使用数组将X-SAMPA语音转录转换为带有相应IPA字符的Unicode字符串.

解决方法

您可以将完全初始化的onject序列化为二进制文件,将该文件作为资源添加,并在启动时将其加载到阵列中.如果构造函数是cpu密集型的,那么您可能会得到改进.由于您的代码似乎执行某种解析,因此获得体面改进的可能性相当高.