C#中如何获取任意字母组合和验证邮件格式

<p style="FONT-SIZE: 10pt">    //产生随机任意字母长度组合    public string RndNum1(int VcodeNum)    {        string Vchar = "0123456789ABCDEFGHIJKLMnopQRSTUVWXYZ";        string VNum = "";        Random rand = new Random();        for (int i = 0; i < VcodeNum; i++)        {            VNum += Vchar[rand.Next(Vchar.Length - 1)].ToString();        }        return VNum;

<p style="FONT-SIZE: 10pt">    }

<p style="FONT-SIZE: 10pt">    //返回:A46U-2VD4 形式的任意字母组合    public string RndNum2(int VcodeNum)    {        string Vchar = "0123456789ABCDEFGHIJKLMnopQRSTUVWXYZ";        string VNum = "";        Random rand = new Random();        for (int i = 1; i <= VcodeNum; i++)        {            if (i % 8 == 0 && i != VcodeNum)            {                VNum += Vchar[rand.Next(Vchar.Length - 1)].ToString() + "-";            }            else            {                VNum += Vchar[rand.Next(Vchar.Length - 1)].ToString();            }        }        return VNum;

<p style="FONT-SIZE: 10pt">    }

<p style="FONT-SIZE: 10pt"> //邮件格式是否正确    public static bool isEmail(string inputEmail)    {        string strRegex = @"\w+([-+.']\w+)@\w+([-.]\w+).\w+([-.]\w+)*";        Regex re = new Regex(strRegex);        if (re.IsMatch(inputEmail))        {            return true;        }        else        {            return false;        }    }