微信公众号搜"智元新知"关注
微信扫一扫可直接关注哦!

javascript – 与’ws:// localhost:3000 /’的WebSocket连接失败:连接在收到握手响应之前关闭

我拍了一个我朋友制作的游戏,希望通过WebRTC和websockets在对等体之间发送按键数据,让它可以跨浏览器播放.但是,我在控制台中收到此错误

WebSocket connection to ‘ws://localhost:3000/’ Failed: Connection closed before receiving a handshake response

我的服务器文件有以下几行:

'use strict';

const express = require('express');
const SocketServer = require('ws').Server;
const path = require('path');

const PORT = process.env.PORT || 3000;
const INDEX = path.join(__dirname, 'index.html');

const server = express();

server.use(express.static(path.join(__dirname, 'lib')));
server.use('/assets', express.static(path.join(__dirname, 'assets')));
server.listen(PORT, () => console.log(`Listening on ${ PORT }`));

const wss = new SocketServer({ server });
var users = {};
let usernames = [];


wss.on('connection', function(connection) {

   connection.on('message', function(message) {

      var data;
      try {
         data = JSON.parse(message);
      } catch (e) {
         console.log("Invalid JSON");
         data = {};
      }

      switch (data.type) {
         case "login":
            console.log("User logged", data.name);
            if(users[data.name]) {
               sendTo(connection, {
                  type: "login",
                  success: false
               });
            } else {
               users[data.name] = connection;
               connection.name = data.name;
               usernames.push(data.name);

               sendTo(connection, {
                  type: "login",
                  success: true,
                  users: usernames
               });
            }

            break;

         case "offer":
            console.log("Sending offer to: ", data.name);
            var conn = users[data.name];

            if(conn != null) {
               connection.otherName = data.name;

               sendTo(conn, {
                  type: "offer",
                  offer: data.offer,
                  name: connection.name
               });
            }

            break;

         case "answer":
            console.log("Sending answer to: ", data.name);
            var conn = users[data.name];

            if(conn != null) {
               connection.otherName = data.name;
               sendTo(conn, {
                  type: "answer",
                  answer: data.answer
               });
            }

            break;

         case "candidate":
            console.log("Sending candidate to:",data.name);
            var conn = users[data.name];

            if(conn != null) {
               sendTo(conn, {
                  type: "candidate",
                  candidate: data.candidate
               });
            }

            break;

         case "leave":
            console.log("disconnecting from", data.name);
            var conn = users[data.name];
            conn.otherName = null;

            if(conn != null) {
               sendTo(conn, {
                  type: "leave"
               });
            }

            break;

         default:
            sendTo(connection, {
               type: "error",
               message: "Command not found: " + data.type
            });

            break;
      }
   });

并且客户端的连接如下所示:

const Game = require("./game");
const GameView = require("./game_view");
var HOST = location.origin.replace(/^http/, 'ws');
console.log('host: ', HOST);
console.log(process.env.PORT);

document.addEventListener("DOMContentLoaded", function() {
  const connection = new WebSocket(HOST);

.....

这是错误发生的点,这是我得到的捕获错误

bubbles
:
false
cancelBubble
:
false
cancelable
:
false
composed
:
false
currentTarget
:
WebSocket
defaultPrevented
:
false
eventPhase
:
0
isTrusted
:
true
path
:
Array(0)
returnValue
:
true
srcElement
:
WebSocket
target
:
WebSocket
timeStamp
:
213.01500000000001
type
:
"error"
__proto__
:
Event

我不太熟悉服务器端编程,并试图理解.我试着查找这个问题,但似乎各种不同的东西都可能导致这个问题.如果您想查看存储库,您可以自己查看并尝试(使用webpack):SlidingWarfare Repo

解决方法:

混乱从这里开始:

const server = express();

express函数并不真正返回服务器,它返回一个应用程序.通常,用于此的变量是app,但这当然不过是约定(即不是要求).

但是,当您将应用程序传递给WS服务器时,它会成为一个问题:

const wss = new SocketServer({ server });

那是因为SocketServer需要一个HTTP服务器实例,哪个服务器不需要.

这是一个修复,没有重命名你的变量:

let httpServer = server.listen(PORT, () => console.log(`Listening on ${ PORT }`));
...
const wss = new SocketServer({ server : httpServer });

(因为当你在Express实例上调用.listen()时,它将返回一个HTTP服务器实例)

使用变量命名约定,它将是这样的:

const app = express();

app.use(express.static(path.join(__dirname, 'lib')));
app.use('/assets', express.static(path.join(__dirname, 'assets')));

let server = app.listen(PORT, () => console.log(`Listening on ${ PORT }`));

const wss = new SocketServer({ server });

版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 [email protected] 举报,一经查实,本站将立刻删除。

相关推荐