javascript – 使用列名称获取商店值

Ext.define('GoogleMarkerModel', {
        extend: 'Ext.data.Model',
        fields: ['Locating','MainPower','Acc','PowerOff','Alarm','Speed','Direction','Latitude','Longitude','DateTime','MainID', 'deviceid','IOState','OilState']
    });

    var MarkerStore = Ext.create('Ext.data.JsonStore', {
        model: 'GoogleMarkerModel',
        autoLoad: true,
        proxy: {
            type: 'ajax',
            url: 'get-googlemarker.PHP',
            baseParams: {  //here you can define params you want to be sent on each request from this store
                        mainid: 'value1'
                        },
            reader: {
                type: 'json',
                root: 'images'
            }
        }
    });

tree.on('checkchange', function(node){
        var data = node.data;
        Ext.MessageBox.show({
        title: 'Changed checkBox status',
        msg: 'MainID: ' + data.MainID + ' <br /> CheckBox status: ' + data.checked,
        icon: Ext.MessageBox.INFO
        });

        if (data.checked == true){
        MarkerStore.load({
                        params: {  //here you can define params on 'per request' basis
                                mainid: data.MainID,
                                }
                        })

        var options = {
        lat:MarkerStore[0].Latitude,
        lng:MarkerStore[0].Longitude,
        marker: {title:"Hello World!"},
        listeners: {
                     click: function(e){

                                         }
                    }     
        }     
        addDoctorLocation(options);           
        }       
    })

这是获得返回值的示例

http://localhost/GPS/examples/tabs/get-googlemarker.PHP?mainid=1

[{"ID":"1808","Locating":"1","MainPower":"0","Acc":"1","PowerOff":"1","Alarm":"128","Speed":"0","Direction":"293","Latitude":"5.391788482666016","Longitude":"100.29693603515625","DateTime":"2013-02-19 15:44:36","MainID":"1","IOState":"0","OilState":"0"}]

这是get-googlemarker.PHP的返回值,
我想在lat变量中保存Latitude值,在longt变量中保存Longitude.像这样的东西：

找到MainID为1的行,并获取列名称纬度值.

更新2

var lati,longi;
        var record = MarkerStore.findRecord('MainID',data.MainID);
        if(record) {
            lati = record.get('Latitude'); 
        longi = record.get('Longitude'); 
        }

记录返回为null,找不到MainID = 1？为什么？ data.MainID值为1.

更新3

Ext.define('GoogleMarkerModel', {
    extend: 'Ext.data.Model',
    idProperty:'MainID',
    fields: ['ID','Locating','MainPower','Acc','PowerOff','Alarm','Speed','Direction','Latitude','Longitude','DateTime','MainID','IOState','OilState']
});

var MarkerStore = Ext.create('Ext.data.JsonStore', {
    model: 'GoogleMarkerModel',
    autoLoad: true,
    proxy: {
        type: 'ajax',
        url: 'get-googlemarker.PHP',
        baseParams: {  //here you can define params you want to be sent on each request from this store
                    mainid: 'value1'
                    },
        reader: {
            type: 'json',
            idProperty : 'MainID',
        }

    }
});

我添加了idProperty,但仍然无法正常工作.

错误

最新代码

tree.on('checkchange', function(node){
        var data = node.data;

        if (data.checked == true){
        MarkerStore.load({
                        params: {  //here you can define params on 'per request' basis
                                mainid: data.MainID,
                                }
                        })


        var lati,longi;
        var recordPos = MarkerStore.findBy(function(rec,id){
             return rec.data.MainID == data.MainID;
        }, this);
        if(recordPos > -1) {
           var record = MarkerStore.getAt(recordPos);
           lati = record.get('Latitude'); 
           longi = record.get('Longitude'); 
        }


        Ext.MessageBox.show({
        title: 'Changed checkBox status',
        msg: 'MainID: ' + data.MainID + ' <br /> CheckBox status: ' + data.checked + ' <br /> lati: ' + lati + ' <br />',
        icon: Ext.MessageBox.INFO
        });

        var options = {
        lat:lati,
        lng:longi,
        marker: {title:"Hello World!"},
        listeners: {
                     click: function(e){

                                         }
                    }     
        }     
        addDoctorLocation(options);           
        }       
    })

仍然无法获得lati值.任何的想法？
如何确定MarkerStore里面有数据？我认为MarkerStore是空的.怎么检查这个？

更新4

var lati,longi;
        var recordPos = MarkerStore.findRecord('MainID', '1');
           lati = recordPos.get('Latitude'); 
           longi = recordPos.get('Longitude');

仍然无法正常工作,recordPos为null.在FIREBUG上发现错误

TypeError: recordPos is null
[Break On This Error]   
lati = recordPos.get('Latitude');

我认为是JSON商店保存PHP数据的问题

更新5

我可以肯定JSON存储有数据,因为我尝试使用此代码打印所有JSON存储数据

MarkerStore.on('load', function(store, records) {
    for (var i = 0; i < records.length; i++) {
    console.log(records[i].get('Latitude'));
    };
});

它在控制台上打印数据

解决方法:

正如sra所说,你可以设置idProperty

var MarkerStore = Ext.create('Ext.data.JsonStore', {
    model: 'GoogleMarkerModel',
    autoLoad: true,
    proxy: {
        type: 'ajax',
        url: 'get-googlemarker.PHP',
        baseParams: {
            mainid: 'value1'
        },
        reader: {
            type: 'json',
            root: 'images',
            idProperty: 'MainId'
        }
    }
});

然后通过MarkerStore.getById(123)或’MarkerStore.findRecord(‘MainId’,123)找到记录’

重要：似乎extjs使用===运算符而不是==来比较两个变量.然后,如果变量具有int类型而另一个具有字符串类型,则比较可能为假(例如,对于“1”=== 1).
那么你应该使用’MarkerStore.findRecord(‘MainId’,’123′)’代替.

javascript – 使用列名称获取商店值 – EXTJS 4

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