如何同时检索每个部门的前3名最高工资和前3名最低工资

如何解决如何同时检索每个部门的前3名最高工资和前3名最低工资

我想知道是否可以使用 sql oracle 或 MysqL 在输出中并排显示来自每个部门的前 3 名最高薪水员工以及同一部门的最低 3 名薪水员工。我尝试使用分析函数和相关子查询方法，但只能获得最高或最低但不能同时获得。对此的任何见解将不胜感激。

DDL 和 DML：

CREATE TABLE "EMP" ( "EMPNO"      NUMBER(4,0),"ENAME"      VARCHAR2(10 BYTE),"JOB"        VARCHAR2(9 BYTE),"MGR"        NUMBER(4,"HIREDATE"   DATE,"SAL"        NUMBER(7,2),"COMM"       NUMBER(7,"DEPTNO"     NUMBER(2,CONSTRAINT "PK_EMP" PRIMARY KEY
 ( "EMPNO" )


Insert into EMP (EMPNO,ENAME,JOB,MGR,HIREDATE,SAL,COMM,DEPTNO) values (7839,'KING','PRESIDENT',null,to_date('17-11-81','DD-MM-RR'),5000,10);
Insert into EMP (EMPNO,DEPTNO) values (8967,'SCott','ANALYST',7566,to_date('27-12-19',3000,DEPTNO) values (7782,'CLARK','MANAGER',7839,to_date('09-06-81',2450,DEPTNO) values (7934,'MILLER','CLERK',7782,to_date('23-01-82',1300,DEPTNO) values (7902,'FORD',to_date('03-12-81',20);
Insert into EMP (EMPNO,DEPTNO) values (8900,DEPTNO) values (7788,to_date('19-04-87',DEPTNO) values (7566,'JOnes',to_date('02-04-81',2975,DEPTNO) values (7876,'AdamS',7788,to_date('23-05-87',1100,DEPTNO) values (7369,'SMITH',7902,to_date('17-12-80',800,DEPTNO) values (7698,'BLAKE',to_date('01-05-81',2850,30);
Insert into EMP (EMPNO,DEPTNO) values (7499,'ALLEN','SALESMAN',7698,to_date('20-02-81',1600,DEPTNO) values (7844,'TURNER',to_date('08-09-81',1500,DEPTNO) values (7654,'MARTIN',to_date('28-09-81',1250,DEPTNO) values (7521,'WARD',to_date('22-02-81',DEPTNO) values (7900,'JAMES',950,30);

解决方法

一种解决方案是：

WITH t AS
    (SELECT e.*,DENSE_RANK() OVER (PARTITION BY DEPTNO ORDER BY sal DESC) AS sal_desc,DENSE_RANK() OVER (PARTITION BY DEPTNO ORDER BY sal ASC) AS sal_ASC
    FROM EMP e)
SELECT * 
FROM t
WHERE sal_desc <= 3 OR sal_ASC <= 3