如何解决如何计算团队和成员
我有一张这样的桌子：
| personid |主管| date_in |
我想计算：
预先感谢您的帮助。
数据：
personid|supervisorid |datein
--------+---------------+----------
001 |NA |01/09/2020
002 |001 |01/09/2020
003 |001 |01/09/2020
004 |003 |01/09/2020
005 |003 |01/09/2020
006 |003 |01/09/2020
007 |003 |01/09/2020
008 |NA |01/09/2020
009 |008 |01/01/1990
010 |008 |01/01/1990
011 |NA |01/01/1990
012 |011 |01/01/1990
结果：
-number of teams:2
-members per team:
supervisor team|num_members
---------------+-----------
001 |7
008 |3
-active teams in the last 30 days: 1 (supervisorid=001)
解决方法
如果您有sas，则可以使用proc sql *“团队”的数量应为不具有主管且至少有两名以下人员的人员数量；
select count(distinct a.personid) as teams
from (select personid from yourtable where supervisorid='NA' group by 1) a
inner join (select supervisorid,count(distinct personid) as num_members from yourtable group by 1) b on a.personid=b.supervisorid ;
*每个团队的成员人数；
select a.person_id as supervisorteam,b.num_members
from(select personid from yourtable where supervisorid='NA' group by 1) a
inner join (select supervisorid,count(distinct personid) as num_members from yourtable group by 1 having num_members>1) b on a.personid=b.supervisorid ;
*“活跃团队”的数量定义为少于X天前添加新人员的团队
select count(distinct a.personid) as active
from (select personid from yourtable where supervisorid='NA' and datein<Xdaysago group by 1) a
inner join (select supervisorid,count(distinct personid) as num_members from yourtable group by 1 having num_members>1) b on a.personid=b.supervisorid ;
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