mysql – 在日期范围内按日期聚合数据,结果集中没有日期间隔

我有一个卖单的表,我想在两个日期之间列出每天的COUNT个卖单,而不会留下日期差距.

这就是我目前所拥有的：

SELECT COUNT(*) as norders, DATE_FORMAT(date, "%M %e") as sdate 
FROM ORDERS 
WHERE date <= Now() 
  AND date >= Now() - INTERVAL 1 MONTH 
GROUP BY DAY(date) 
ORDER BY date ASC;

我得到的结果如下：

6     May 1
14    May 4
1     May 5
8     Jun 2
5     Jun 15

但我想得到的是：

6     May 1
0     May 2
0     May 3
14    May 4
1     May 5
0     May 6
0     May 7
0     May 8
.....
0     Jun 1
8     Jun 2
.....
5     Jun 15

那可能吗？

解决方法:

动态创建一系列日期并加入针对您的订单表： –

SELECT sub1.sdate, COUNT(ORDERS.id) as norders
FROM
(
    SELECT DATE_FORMAT(DATE_SUB(Now(), INTERVAL units.i + tens.i * 10 + hundreds.i * 100 DAY), "%M %e") as sdate 
    FROM (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9)units
    CROSS JOIN (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9)tens
    CROSS JOIN (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9)hundreds
    WHERE DATE_SUB(Now(), INTERVAL units.i + tens.i * 10 + hundreds.i * 100 DAY) BETWEEN DATE_SUB(Now(), INTERVAL 1 MONTH) AND Now()
) sub1
LEFT OUTER JOIN ORDERS
ON sub1.sdate = DATE_FORMAT(ORDERS.date, "%M %e")
GROUP BY sub1.sdate

这可以应对最多1000天的日期范围.

请注意,根据您在日期中使用的字段类型,可以更轻松地提高效率.

编辑 – 根据要求,获取每月订单数量： –

SELECT aMonth, COUNT(ORDERS.id) as norders
FROM
(
    SELECT DATE_FORMAT(DATE_SUB(Now(), INTERVAL months.i MONTH), "%Y%m") as sdate, DATE_FORMAT(DATE_SUB(Now(), INTERVAL months.i MONTH), "%M") as aMonth 
    FROM (SELECT 0 i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10 UNION SELECT 11)months
    WHERE DATE_SUB(Now(), INTERVAL months.i MONTH) BETWEEN DATE_SUB(Now(), INTERVAL 12 MONTH) AND Now()
) sub1
LEFT OUTER JOIN ORDERS
ON sub1.sdate = DATE_FORMAT(ORDERS.date, "%Y%m")
GROUP BY aMonth