=>背景介绍
->tableSales表
->第一次查询(2013销售员销售总额)
select salesName,sum(extendedPrice) as sumprice13 from tableSales where salesTime between '2013-01-01' and '2013-12-31' group by salesName
->第二次查询(2014销售员销售总额)
select salesName,sum(extendedPrice) as sumprice14 from tableSales where salesTime between '2014-01-01' and '2014-12-31' group by salesName
->如何获得销售员13、14年的销售总额？
A、首先，我想到的就是用union all，但不理想；
select salesName,sum(extendedPrice) as sumprice13,null as sumprice14 from tableSales where salesTime between '2013-01-01' and '2013-12-31' group by salesName
union all
select salesName,null as sumprice13,sum(extendedPrice) as sumprice14 from tableSales where salesTime between '2014-01-01' and '2014-12-31' group by salesName
B最后，通过fredrickhu版主大大的指点，修改如下：
SELECT
a.salesName,a.sumprice13,b.sumprice14
FROM
(SELECT
salesName,SUM(extendedPrice) AS sumprice13
FROM
tableSales
WHERE
salesTime BETWEEN '2013-01-01' AND '2013-12-31'
GROUP BY
salesName
) AS a
INNER JOIN
(SELECT
salesName,SUM(extendedPrice) AS sumprice14
FROM
tableSales
WHERE
salesTime BETWEEN '2014-01-01' AND '2014-12-31'
GROUP BY
salesName
) AS b
ON a.salesName=b.salesName
最后再次感谢fredrickhu大大！谢谢！..风雨兼程...
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