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关于SQLServer2005的学习笔记——子查询

SQL Server 的子查询给人的感觉一向不是很好用, IN 查询无法实现多列的子查询,很多情况下又需要进行自我的子查询操作,比如取员工的最新订单之类的问题。

以下 sql 和案例来之于 <sqlServer2005 技术内幕 T-sql 查询 > 一书,不过适当的做了些编排和自己的理解。

 

让我们先来看看 Oracle 是怎么处理子查询

CREATE TABLE Orders

(

  OrderID     VARCHAR2(6),

  CustomerID  VARCHAR2(6),

  EmployeeID  INT,

  OrderDate   DATE

);

TruncATE TABLE Orders;

INSERT INTO Orders VALUES('110001','WBQ',1,TO_DATE('2000-01-11','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110002',TO_DATE('2000-01-21','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110003',2,'YYYY-MM-DD'));

INSERT INTO Orders VALUES('110004',3,TO_DATE('2000-02-01','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110005','CZH','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110006',TO_DATE('2000-03-01','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110007','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110008','KIDD','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110009',TO_DATE('2000-04-01','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110010','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110011','YYYY-MM-DD'));

INSERT INTO Orders VALUES('110012',TO_DATE('2000-01-10','YYYY-MM-DD'));

COMMIT;

SELECT EmployeeID,OrderDate,OrderID,CustomerID

  FROM Orders

  ORDER BY EmployeeID,OrderID

 

-- 层递直至实现唯一为止

SELECT EmployeeID,CustomerID

  FROM Orders

  WHERE (EmployeeID,OrderID) IN

       (SELECT EmployeeID,MAX(OrderID)

          FROM Orders

         WHERE (EmployeeID,OrderDate) IN

               (SELECT EmployeeID,Max(OrderDate)

                  FROM Orders

                 GROUP BY EmployeeID)

         GROUP BY EmployeeID,OrderDate)

  ORDER BY EmployeeID,CustomerID

 

-- 多值,通常情况下该语句即可,不过在本例中 EmployeeID,OrderDate 并不唯一,导致结果非所需的

SELECT EmployeeID,OrderDate) IN

       (SELECT EmployeeID,Max(OrderDate)

          FROM Orders

         GROUP BY EmployeeID)

  ORDER BY EmployeeID,CustomerID

 

--Error ,这是个错误的表达式

SELECT EmployeeID,MAX(OrderDate),MAX(OrderID)

          FROM Orders

         GROUP BY EmployeeID)

 

-- 使用分析函数,也可以实现相应的子查询       

SELECT EmployeeID,CustomerID FROM

(

  SELECT EmployeeID,CustomerID,

         RANK() OVER (PARTITION BY EmployeeID ORDER BY OrderDate DESC,OrderID DESC) Rank

    FROM Orders

) a

  WHERE a.Rank=1

 

 

让我们继续看看 sql Server 是如何处理的

CREATE TABLE Orders

(

  OrderID     VARCHAR(6),

  CustomerID  VARCHAR(6),

  OrderDate   DATETIME

);

INSERT INTO Orders VALUES('110001','2000-01-11');

INSERT INTO Orders VALUES('110002','2000-01-21');

INSERT INTO Orders VALUES('110003','2000-01-11');

INSERT INTO Orders VALUES('110004','2000-02-01');

INSERT INTO Orders VALUES('110005','2000-02-01');

INSERT INTO Orders VALUES('110006','2000-03-01');

INSERT INTO Orders VALUES('110007','2000-03-01');

INSERT INTO Orders VALUES('110008','2000-02-01');

INSERT INTO Orders VALUES('110009','2000-04-01');

INSERT INTO Orders VALUES('110010','2000-03-01');

INSERT INTO Orders VALUES('110011','2000-02-01');

INSERT INTO Orders VALUES('110012','2000-01-10');

COMMIT;

 

-- 多值,通常情况下该语句即可,不过在本例中 EmployeeID,CustomerID

  FROM Orders O1

  WHERE rderDate=

       (SELECT MAX(OrderDate)

          FROM Orders O2

         WHERE O1.EmployeeID=O2.EmployeeID)

  ORDER BY EmployeeID,CustomerID

等效于 Oracle 的以下语句

SELECT EmployeeID,CustomerID

 

正确的 sqlServer 查询写法,用两个 MAX 求得唯一值

SELECT EmployeeID,CustomerID

  FROM Orders O1

  WHERE rderDate=

       (SELECT MAX(OrderDate)

          FROM Orders O2

         WHERE O1.EmployeeID=O2.EmployeeID)

   AND rderID=

        (SELECT Max(OrderID)

          FROM Orders O2

         WHERE O1.EmployeeID=O2.EmployeeID

           AND O1.OrderDate=O2.OrderDate)

  ORDER BY EmployeeID,CustomerID

 

-- 本例使用一种变通的方法,把几个应有的附加条件加进来然后返回,比较难以理解

SELECT

  CAST(SUBSTRING(BinStr,8) AS DATETIME) AS OrderDate,

  CAST(SUBSTRING(BinStr,9,6) AS VARCHAR) AS OrderID,15,6) AS VARCHAR) AS CustomerID

FROM (SELECT EmployeeID,

             MAX(CAST(OrderDate AS BINARY(8))

                +CAST(OrderID AS BINARY(6))

                +CAST(CustomerID AS BINARY(6))) AS BinStr

        FROM Orders

       GROUP BY EmployeeID) D;

 

-- 本例中在子查询中使用 TOP+Order 排序的方式获取相应的第一行值

SELECT EmployeeID,CustomerID

  FROM Orders O1

  WHERE rderID=

  (SELECT TOP(1) OrderID

     FROM Orders O2

    WHERE O1.EmployeeID=O2.EmployeeID

    ORDER BY OrderDate DESC,OrderID DESC,CustomerID

   )

  ORDER BY EmployeeID,CustomerID

 

-- 本例使用了 IN 查询,可以自定义返回的 TOP N 条数

SELECT EmployeeID,CustomerID

  FROM Orders O1

  WHERE OrderID IN

  (SELECT TOP(1) OrderID

     FROM Orders O2

    WHERE O1.EmployeeID=O2.EmployeeID

    ORDER BY OrderDate DESC,CustomerID

   )

ORDER BY EmployeeID,CustomerID

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