微信公众号搜"智元新知"关注
微信扫一扫可直接关注哦!

update关联更新在sqlserver和oracle中的实现

sqlserver和oracle中实现update关联更新的语法不同,都可以通过inline view(内嵌视图)
来实现,总的来说sqlserver更简单些. 测试例子如下:


create table tmp_a
(cpcode varchar2(10),
sb_ym varchar2(6),
flag char(1)
);

create table tmp_b
(cpcode varchar2(10),
flag char(1)
);

insert into tmp_a(cpcode,sb_ym,flag)values('3201910001','200406','e');
insert into tmp_a(cpcode,flag)values('3201910002','e');
insert into tmp_b(cpcode,'r');
insert into tmp_b(cpcode,flag)values('3201910003',flag)values('3201910004','e');
commit;

sqlSERVER中:

update tmp_b set flag = b.flang from tmp_a a,tmp_b b
where a.cpcode =b.cpcode and a.sb_ym = b.sb_ym;


在Oracle中:

方法一:(效率低)
update tmp_b a
set flag = (select flag from tmp_a b
where a.cpcode = b.cpcode and a.sb_ym = b.sb_ym )
where exists
(select * from tmp_a c
where a.cpcode = c.cpcode and a.sb_ym = c.sb_ym);

Statistics
----------------------------------------------------------
8 recursive calls
3 db block gets
18 consistent gets
0 physical reads
0 redo size

方法二:(效率高)
alter table tmp_a add constraint p_tmp_a primary key (cpcode,sb_ym);

update (select b.flag flagb,a.flag flaga
from tmp_a a,tmp_b b
where a.cpcode=b.cpcode
and a.sb_ym=b.sb_ym)
set flagb=flaga;

Statistics
----------------------------------------------------------
0 recursive calls
3 db block gets
7 consistent gets
0 physical reads
0 redo size

注意:方法二中数据源表必须要加上主键,否则会报错 ORA-01779: 无法修改与非键值保存表对应的列被修改的表则无需增加主键

 

版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 [email protected] 举报,一经查实,本站将立刻删除。

相关推荐