python – 熊猫时间序列多片

我可以从pandas文档中看到你可以去：

df.loc[['a','b','c'],:]

对于时间序列,为什么你不去：

x = df.loc[['2005-10-27 14:30':'2005-10-27 15:15', '2006-04-14 14:40':'2006-04-14 15:20', '2008-01-25 14:30':'2008-01-25 15:30'],:]

我收到语法错误.你能否在时间序列上做多个切片范围？有解决方法吗？

解决方法:

虽然DataFrame索引将接受列索引列表,但它不接受行切片对象列表.

这应该做你想要的,它循环你所需的范围编译一个新的DataFrame.

import numpy as np
import pandas as pd

# let's create some fake data
date_range = pd.date_range('2005-01-01', '2008-12-31', freq='9min')
l = len(date_range)
df = pd.DataFrame({'normal': np.random.randn(l), 'uniform':np.random.rand(l), 
    'datetime':date_range, 'integer':range(l)}, index=date_range)

# let's identify the periods we want
desired = [('2005-10-27 14:30','2005-10-27 15:15'), 
           ('2006-04-14 14:40','2006-04-14 15:20'), 
           ('2008-01-25 14:30','2008-01-25 15:30')]

# let's loop through the desired ranges and compile our selection           
x = pd.DataFrame()
for (start, stop) in desired:
    selection = df[(df.index >= pd.Timestamp(start)) & 
        (df.index <= pd.Timestamp(stop))]
    x = x.append(selection)

# and let's have a look at what we found ...
print(x)