>>> import pandas as pd
>>> import numpy as np
>>> a = pd.DataFrame(np.array([[2, 1990], [4,1991], [5,1992]]), \
... index=[1,2,3], columns=['var', 'yr'])
>>> a
var yr
1 2 1990
2 4 1991
3 5 1992
>>> b = pd.DataFrame(index=a.index, columns=['new_var'])
>>> b
new_var
1 NaN
2 NaN
3 NaN
>>> b[a.yr<1992].loc[:, 'new_var'] = a[a.yr<1992].loc[:, 'var']
>>> b
new_var
1 NaN
2 NaN
3 NaN
我希望以下输出:
>>> b
new_var
1 2
2 4
3 NaN
解决方法:
改为:
b.loc [a.yr< 1992,'new_var'] = a ['var']
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