我有一个用户的表,其中有3列,我正在尝试计数,然后按created_at日期分组.
列:’created_at’,’answers_count’,’questions_count’
如何将这3个查询合并为一个,并将所有计数按相同的created_at日期分组?
这是3个单独的查询:
-- daily new signups
SELECT date_trunc('day', users.created_at) AS signup_date, count(*) AS new_users
FROM users
GROUP BY signup_date
ORDER BY signup_date DESC;
-- new user answers_count by signup date
SELECT date_trunc('day', users.created_at) AS signup_date, count(*) AS answers_count
FROM users
WHERE users.answers_count > 0
GROUP BY signup_date
ORDER BY signup_date DESC;
-- new user questions_count by signup date
SELECT date_trunc('day', users.created_at) AS signup_date, count(*) AS qs_received
FROM users
WHERE users.questions_count > 0
GROUP BY signup_date
ORDER BY signup_date DESC;
解决方法:
您应该尝试使用带有CASE的SUM()来完成此任务.
尝试这样的事情:
SELECT date_trunc('day', users.created_at) AS signup_date,
count(*) AS new_users,
sum(case when answers_count > 0 then 1 else 0 end) as answers_count,
sum(case when questions_count > 0 then 1 else 0 end) as qs_received,
FROM users
GROUP BY signup_date
ORDER BY signup_date DESC;
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 [email protected] 举报,一经查实,本站将立刻删除。