我有三个表:用户,项目和板.
create table users ( id serial primary key,name text ); create table items ( id serial primary key,user_id int,title text ); create table boards ( id serial primary key,title text );n
select users.*,count(items) as item_count,count(boards) as board_count from users left join items on items.user_id = users.id left join boards on boards.user_id = users.id group by users.id;
问题是由两个左连接产生重复值的事实引起的.
要解决此问题,您可以只计算不同的值
SELECT u.id,u.name,COUNT(disTINCT i.id) item_count,COUNT(disTINCT b.id) board_count FROM users u LEFT JOIN items i ON u.id = i.user_id LEFT JOIN boards b ON u.id = b.user_id GROUP BY u.id,u.name
SELECT u.*,COALESCE(i.item_count,0) item_count,COALESCE(b.board_count,0) board_count FROM users u LEFT JOIN ( SELECT user_id,COUNT(*) item_count FROM items GROUP BY user_id ) i ON u.id = i.user_id LEFT JOIN ( SELECT user_id,COUNT(*) board_count FROM boards GROUP BY user_id ) b ON u.id = b.user_id
这是SQLFiddle演示
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