spark 通过传入List 创建DataFrame

spark创建dataFrame方式有很多种，官方API也比较多，可能用的最多的是通过textFile()读取数据源吧

但是业务上的个别场景，不适合用textFile()，于是使用下面的这个API

  /**
   * Applies a schema to a List of Java Beans.
   *
   * WARNING: Since there is no guaranteed ordering for fields in a Java Bean,
   *          SELECT * queries will return the columns in an undefined order.
   * @since 1.6.0
   */
  def createDataFrame(data: java.util.List[_], beanClass: Class[_]): DataFrame = {
    val attrSeq = getSchema(beanClass)
    val rows = sqlContext.beansToRows(data.asScala.iterator, beanClass, attrSeq)
    Dataset.ofRows(self, LocalRelation(attrSeq, rows.toSeq))
  }

　　

样例部分代码：

ArrayList<GciGri> list = new ArrayList<GciGri>();
    GciGri g = new GciGri();
    g.setGci((gci));
    g.setGri((gri));
    list.add(g);

spark.createDataFrame(list, GciGri.class).createOrReplaceTempView("testtesttest");

　　

package cn.com.dtmobile.test;

import java.io.Serializable;

public class GciGri implements Serializable {
	
	private static final long serialVersionUID = 1L;
	
    private int Gci;
    private int Gri;
    
	public int getGci() {
		return Gci;
	}
	public void setGci(int gci) {
		Gci = gci;
	}
	public int getGri() {
		return Gri;
	}
	public void setGri(int gri) {
		Gri = gri;
	}
    
    
}