Swift中的多态性(如果没有)

我在 swift中有这个代码：解释多态的想法！

//polymorphism


class Person {
var name:String="Guest"
var age:Int=0

init(name:String) {
    self.name=name
    self.age=0
}
init(name:String,age:Int) {
    self.name=name
    self.age=age
}

func Update(name:String) {
    self.name=name
}
func Upgrade() {
    self.age++
}
}



class Student:Person
{
var average:Float=100
func IsOk()->Bool {
    return average > 80
}
init(name:String,average:Float) {
    super.init(name: name)
    self.average=average
}
}


class Teacher:Person {
var Salary:Float=2000
init(name:String,age:Int,Salary:Float){
    super.init(name: name,age: age)
    self.Salary=Salary

}
func GetNetSalary()->Float {
    return 0.8*self.Salary
}

override func Upgrade() {
    super.Upgrade()
    Salary*=1.1 // add 10% to salary
}
}



var t1:Teacher=Teacher(name: "Ahmed",age: 28,Salary: 3000)
var st1=Student(name:"Test",average: 70)

var p1:Person=Person(name: "abc")
var p2:Person=Student(name: "Student1",average: 100) //up casting
var p3:Person=Teacher(name: "Teacher",age: 40,Salary: 3008)


var arr=[t1,st1,p1,p2,p3] //array of persons and teachers and students

for instance in arr {
if instance is Student {println("This is student")}
if instance is Teacher {println("This is teacehr")}  
}

在for循环的最后我怎么能把这样的条件看看数组中的元素是否只是一个Person？
因为当我输入：

if instance is Person {println("This is a Person")}

这给了我一个错误,因为这个条件总是正确的！

解决方法

EDITED

你在问：

How Could I put such a condition to see if an element in the array is only a Person?

在强大的静态类型语言中,您无法访问对象的运行时类型,您无法执行此操作.但是,在Swift中,您可以通过dynamicType方法使用该语言的自反属性来获取此类型.