覆盖swift中的泛型函数错误

这是代码：

class Test<T> { 
    func foo<S:SequenceType where S.Generator.Element == T>(par : S){
        print("foo")
    }
}
class TestInh : Test<Int> { 
    override func foo<S:SequenceType where S.Generator.Element == Int>(par : S) { 
        print("loo")
    } 
}

它大喊这样的错误：

repl.swift:8:19: error: method does not override any method from its superclass
    override func foo<S:SequenceType where S.Generator.Element == Int>(par : S) {
    ~~~~~~~~      ^

如何在超类Test< Int>？中覆盖该方法？

==================额外=======================

谈到代码打击.

class Test<T> { 
    func foo(par : T){
        print("foo")
    }
}
class TestInh : Test<Int> { 
    override func foo(par : Int) { 
        print("loo")
    } 
}

一切正常.不知道哪里发生了什么声明.

解决方法

从泛型类继承非泛型类时,您应该：

>使用非泛型方法覆盖;但
>不使用通用覆盖.

在这两种情况下,您仍然可以调用所述方法的超级实现.

因此,这应该工作：

class Base<T> {
    func testGeneric<S: SequenceType where S.Generator.Element == T>(sequence: S) {
        print("Base \(__FUNCTION__)(sequence: \(sequence.dynamicType))")
    }

    func testNongeneric(element: T) {
        print("Base \(__FUNCTION__)(element: \(element.dynamicType))")
    }
}

class Subclass: Base<Int> {
    func testGeneric<S: SequenceType where S.Generator.Element == Int>(sequence: S) {
        super.testGeneric(sequence)
        print("Subclass \(__FUNCTION__)(sequence: \(sequence.dynamicType))")
    }

    override func testNongeneric(element: Int) {
        super.testNongeneric(element)
        print("Subclass \(__FUNCTION__)(element: \(element.dynamicType))")
    }
}

测试：

let base = Base<Double>()
let subclass = Subclass()

base.testGeneric([])        // Prints: Base testGeneric(sequence: Array<Double>)
subclass.testGeneric([])    // Prints: Base testGeneric(sequence: Array<Int>)
                            //         Subclass testGeneric(sequence: Array<Int>)

base.testNongeneric(0)      // Prints: Base testNongeneric(element: Double)
subclass.testNongeneric(0)  // Prints: Base testNongeneric(element: Int)
                            //         Subclass testNongeneric(element: Int)