如何调用别人提供的webservice接口

传递对方的url,方法名，参数信息。不需要引用对方的代码。

测试跑通。

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package com.flyfox.client;

import org.apache.axis.client.Call; import org.apache.axis.client.Service; public class HelloWorldServiceClient {     public static void main(String[] args) throws Exception {         Service service = new Service();         try {             Call call = (Call) service.createCall();             call                     .setTargetEndpointAddress("http://172.16.192.73:8080/np-fy-ajpc/services/ajpcTjpcService?wsdl");             call.setoperationName("tjpcProcess");             call.addParameter(                 "xmlParam",//设置要传递的参数                 org.apache.axis.encoding.XMLType.XSD_STRING,                javax.xml.rpc.ParameterMode.IN);             call.setReturnType(org.apache.axis.encoding.XMLType.XSD_STRING);             //            call.setTimeout(5000);             call.setUseSOAPAction(true);             call                     .setSOAPActionURI("http://support.ajpc.fy.np.thunisoft.com/tjpcProcess");             String result = (String) call                     .invoke(new Object[] { "<QueryParam NAjlb='1' NSpcx='2' CBhAj='6A10F8068A8015310BA2887DEFFC8960' NSyfy='1'></QueryParam>" });             System.out.println(result);         } catch (Exception ex) {             ex.printstacktrace();         }     } }