我正在尝试查询MySQL到ORDER然后GROUP …这是一个很多问题,我找到了一个似乎与我相关的答案:Getting a MySQL group by query to display the row in that group with the highest value
但是我发现在进行分组之前它仍然没有订购.
具体来说,我要做的是使用wordpress自定义帖子类型按名称为“日期”的元数据字段进行分组,按发布日期排序.
这是我的查询:
SELECT
`ID`, `date`, `post_date`, `date_rank`
FROM (
SELECT
`Post`.`ID`,
`Post`.`post_date`,
`PostData`.`Meta_value` AS `date`,
CASE
WHEN @data_date = `PostData`.`Meta_value` THEN @rowum := @rownum + 1
ELSE @rownum := 1
END AS date_rank,
@data_date := `PostData`.`Meta_value`
FROM
`".$this->wpdb->posts."` AS `Post`
JOIN
`".$this->wpdb->postMeta."` AS `PostData`
ON `Post`.`ID` = `PostData`.`post_id` AND `PostData`.`Meta_key` = 'date'
JOIN (SELECT @rownum := 0, @data_date := '') AS `vars`
WHERE
`Post`.`post_type` = 'my_post_type'
AND
`Post`.`post_status` = 'publish'
ORDER BY `Post`.`post_date` DESC
) AS `x`
WHERE date_rank = 1
ORDER BY `date` ASC
所需的结果是每个“日期”的帖子(这是一个元字段),根据post_date显示此“日期”的最新帖子.
解决方法:
SELECT *
FROM (
SELECT disTINCT Meta_value
FROM postdata pd
WHERE pd.Meta_key = 'date'
) pd
JOIN post p
ON p.id =
(
SELECT post_id
FROM postdata pdi
JOIN post pi
ON pi.id = pdi.post_id
WHERE pdi.Meta_key = 'date'
AND pdi.Meta_value = pd.Meta_value
ORDER BY
pi.post_date DESC, pi.id DESC
LIMIT 1
)
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